marshallmattah
04.11.2020 •
Chemistry
If 5.90 kJ of heat evolved from a neutralization of 156 mmols of a monoprotic acid, what is the molar heat of neutralization (in kJ/mol) of that acid
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Ответ:
37.82kJ/mol is the molar heat of neutralization
Explanation:
The neutralization of a monoprotic acid, HX, with NaOH as example is:
HX + NaOH → H₂O + NaX + ΔH
Where ΔH is molar heat of neutralization (The heat that is released when 1 mole of HX is neutralized).
As neutralization of 156mmol = 0.156mol HX release 5.90kJ. When 1 mole is neutralized the released heat is:
ΔH = 5.90kJ / 0.156moles
ΔH = 37.82kJ/mol is the molar heat of neutralization
Ответ:
it is a sign convention that clockwise rotation is negative.
counter clock wise rotation is positive
upward movement is taken as positive
downward movement is taken as negative.