If 50 ml of 1.00 M of H2SO4 and 50 ml of 2.0 M KOH are mixed what is the concentration of the resulting solutes?

0.5 M

Explanation:

First, let us look at the balanced equation of the reaction.

The solute formed is .

Recall that: mole = molarity x volume

Hence,

50 ml, 1.00 M H2SO4 = 0.05 x 1 = 0.05 mole

50 ml, 2.0 M KOH = 0.05 x 2 = 0.1 mole

From the equation

1 mole of H2SO4 reacts with 2 moles of KOH to give 1 mole of K2SO4.

Hence,

0.05 mole H2SO4 reacting with 0.1 mole KOH will give 0.05 mole .

Also recall that: concentration = mole/volume

Total volume of resulting solution = 50 ml + 50 ml = 100 ml or 0.1 liter

Concentration of = mole of /volume of resulting solution

                              = 0.05/0.1 = 0.5 M

The concentration of the resulting solute = 0.5 M

It is critical in the process of ceeluar reespiration.

Explanation:

Water is critical in the process of cellular respiration, which is required for us to extract the energy we do from food. It DOES NOT capture sunlight in photosynthesis. In the first stage of photosynthesis, energy from the sun is captured to make glucose molecules, and oxygen from the water molecules is GIVEN OFF AS WASTE in the process.