If 72.5 grams of calcium metal (ca) react with 65.0 grams of oxygen gas (o2) in a synthesis reaction, how many grams of the excess reactant will be left over when the reaction is complete? be sure to write out the balanced equation for this reaction and to show all of your work.
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Ответ:
First, determine which is the excess reactant
72.5 g Ca (1 mol) =1.8089725036
(40.078 g)
65 g O2 (1 mol) =2.0313769611
(15.999g × 2)
Since the ratio of to O2 is 2:1 in the balanced reaction, divide Ca's molar mass by 2 to get 0.9044862518. this isn't necessary because Ca is already obviously the limiting reactant. therefore, O2 is the excess reactant.
Now do the stoichiometry
72.5 g Ca (1 mol Ca) (1 mol O2)
(40.078 g Ca)(2 mol Ca)(31.998g O2)
=0.0282669621 g of O2 left over
Ответ:
Ionic bonds are characterized by a transfer of electrons between elements to form a stable compound. These bonds typically form in compounds consisting of a metal and a nonmetal, which are positively and negatively charged respectively.
Covalent bonds are characterized by a sharing of electrons between the elements in the compound. Covalent bonds are formed between nonmetals and in many inorganic compounds as well.
Metallic bonding, as the name suggests, is formed between metals.
Since phosphorus pentoxide consists of 4 phosphorus atoms and 10 oxygen atoms, and both of which are categorized as nonmetals, phosphorus pentoxide is therefore, bonded covalently.