Valduarte07
17.07.2019 •
Chemistry
If a 10.0 g mass of aluminum increases from 20.0 °c to 35.0 °c, how much heat was required? (0.903 j/g°c)
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Ответ:
q= m x Ce x ΔT
q= heat
m= mass
Ce= specific heat
ΔT= change in temperature
m= 10.0 g
Ce = 0.903 J/gC
ΔT = Tf - Ti = 35.0 - 20.0= 15
q= 10.0g x 0.903 J/gC x 15 = 135.45 J
Ответ: