If monosaccharide has 11 oxygen atoms, how many hydrogen atoms does it contain

The general chemical formula of a monosaccharide can be written as:

(CH2O)x

where x is the number of carbon or oxygen atoms

We can actually see that each carbon or oxygen atom requires 2 hydrogen atoms, therefore for a compound with 11 oxygen atoms, there would be:

22 Hydrogen atoms

Actual yield for the reaction is 38.5 g of NaCl

Explanation:

The balanced equation is this:

2 Na(s) + Cl₂ (g) → 2NaCl (s)

Ratio is 2:2. Let's determine the moles of sodium metal that has reacted.

17.25 g . 1 mol /23 gl = 0.75 moles

0.75 moles of Na were  used to produced 0.75 moles of NaCl, according to the equation.

Let's determine the mass of NaCl, that were produced.

0.75 mol . 58.45 g / 1 mol = 43.8 g

43.8 will be the theoretical yield (100%). Let's determine the 88%.

(Yield reaction / Theoretical yield) . 100 = 88

Yield reaction / 43.8 g = 88 / 100

Yield reaction = 0.88 . 43.8 g → 38.5  g