If the density of ocean water at a depth of 1.00 x 104 m is 1.071 g/ml and if 21.0 g of water at that depth contains 197 mg of potassium chloride, what is the molarity of potassium chloride in the sample
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Ответ:
The molarity concentration is simply the ratio of the number of moles of solute over the total volume of the solution.
The molar mass of potassium chloride is 74.55 g/mol, so the moles is:
moles KCl = 0.197 g / (74.55 g/mol) = 2.64 x 10^-3 mol
Assuming that the volume of KCl is negligible so that the total volume of solution is simply equal to the volume of water, so:
Volume = 21 g / [(1.071 g / mL) * (1000 mL / 1 L)] = 0.0196 L
So the molarity is:
Molarity = 2.64 x 10^-3 mol / 0.0196 L
Molarity = 0.135 moles / L = 0.135 M
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