Chemistry: If the person in the figure wants his shadow to be 3 feet long, how far should he move and in what direction?See attached photo.sorry this is not chemistry I clicked the wrong subject

If the person in the figure wants his shadow to be

khikhi1705

18.01.2022

3 2/3 ft to the right

Explanation:

The picture of the question in the attached figure N 1

To better understand the problem see that attached figure with letters N 2

we know that

If two figures are similar, then the ratio of its corresponding sides is proportional

In this problem

Triangle A.D.F is similar to Triangle B.D.E ----> by AA Similarity Theorem

$\frac{A.F}{B.E}=\frac{F.D}{E.D}$

we have

$A.F=15\ ft\\B.E=6\ ft\\F.D=(10+E.D)\ ft$

substitute

$\frac{15}{6}=\frac{10+E.D}{E.D}$

solve for E.D

$15E.D=60+6E.D\\9E.D=60\\\\E.D=\frac{20}{3}\ ft$

E.D is the length of the shadow

The person should move to the right x feet

$x=\frac{20}{3}-3\\\\x=\frac{11}{3}\ ft$

convert to mixed number

$\frac{11}{3}\ ft=\frac{9}{3}+\frac{2}{3}=3\frac{2}{3}\ ft$

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