If we had 11.3 g of nitrogen and 2 g of hydrogen, how much nitrogen would remain if all the hydrogen was consumed? g

3H2 + N2 > 2NH3

This means that each 6 grams of hydrogen react with 28 grams of nitrogen. To know how many grams of nitrogen are required to react with 2 grams of hydrogen, we will simply do cross multiplication as follows:

mass of nitrogen = (2 x 28) / 6 = 9.334 grams

Therefore, if we have 11.3 grams of nitrogen, 9.334 grams would react with 2 grams of hydrogen.

remaining mass of nitrogen = 11.3 - 9.334 = 1.966 grams

1024 I think that's right