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IsaacRodriguez245
06.08.2019 •
Chemistry
If you combine 27.1 g of a solute that has a molar mass of 27.1 g/mol with 100.0 g of a solvent, what is the molality of the resulting solution?
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Ответ:
The molality of the solution is 0.1 m.
Explanation:
To calculate the molality of solution, we use the equation:
Where,
Putting values in above equation, we get:
Hence, the molality of the solution is 0.1 m.
Ответ:
the molality of the solution is 10 mol/kg
Explanation:
To find the molality of a solution we apply the following formula
data:
100 g of solvente
We have the amount of solvent expressed in grams but to be able to use the data in the formula we must pass it to kilograms
we apply a simple rule of three
27.1g of solute, molar mass 27.1 g/mol
We need the moles of solute and they give us grams of solute and molar mass
The molar mass is 27.1 g / mol This means that there is 27.1 g for each mol of solute.
The amount of solute we have is 27.1g and according to the molar mass this amount of solute corresponds exactly to 1 mole
Therefore having 27.1 g of solute is equivalent to saying that we have 1 mol of solute
Now that we have the data in the correct units we apply the formula
the molality of the solution is 10 mol/kg
Ответ:
Answer : The weight of water is 9 g
Explanation:
According to avogadro's law, 1 mole of every substance weighs equal to its molecular mass and contains avogadro's number
of particles.
To calculate the number of moles, we use the equation:
1 mole of water
weighs = 18 g
0.5 moles of water
weighs = ![\frac{18}{1}\times 0.5=9g](/tpl/images/0720/0609/edba3.png)
Thus the weight of water is 9 g