Chemistry: If you were making S’mores [using a chocolate bar, gram-crackers, and marshmallows] at a campfire, would this process be considered a chemical reaction?

The final temperature of the system is 32.4 °C.heat lost by Pb + heat gained by water = 0Adding and and combinibg like terms, we get...

If you were making S’mores [using a chocolate

Ответ:

Jamie228

29.01.2022

Chemistry

The process of making S'more by adding chocolate bar, gram-crackers, and marshmallows in layers is not a chemical reaction

Explanation:

In a chemical reaction, the substances involved in the reaction are known as the reactants and the substances produced have different physical and chemical properties than those of the reactants and they are known as the products.

The bonds that hold the atoms of the reactants are broken down and rearranged, creating entirely new substances as products. Therefore, energy must be added and/or evolved in any chemical reaction and all reactant atoms should be involved in the reaction.

The change in energy can be sensed as heat change such as increase or decrease in the temperature of the products

Since S'more does not involve any of the above changes that occur in a chemical reaction when the chocolate bar, gram-crackers, and marshmallows are put together, it is not a chemical change or a chemical reaction.

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Ответ:

Hiadamcom

14.05.2023

Chemistry

The final temperature of the system is 32.4 °C.

heat lost by Pb + heat gained by water = 0

$q_{1} +q_{2} = 0$

$m_{1}C_{1}\Delta T_{1} + m_{2}C_{2}\Delta T_{2} = 0$

$q_{1}= m_{1}C_{1}\Delta T_{1} = 21.2 \:\text{g}\times 0.128\: \text{J}^{\circ}\text{C}^{-1}\text{g}\times (T_{f} -113\: ^{\circ}\text{C}) = 2.713T_{f}\: \text{J}^{\circ}\text{C}^{-1}\: -\: 306.6\:\text{J}\cdot\text{g}^{-1}\\$

$q_{2}= m_{2}C_{2}\Delta T_{2} = 14.8 \:\text{g}\times 4.184\: \text{J}\cdot^{\circ}\text{C}^{-1}\text{g}^{-1}\times (T_{f} -28.9\: ^{\circ}\text{C}) = 61.9\: \Delta T_{f} \: \text{J}^{\circ}\text{C} \:- 1790 \: \text{J}\\$

Adding $q_{1}$ and $q_{2}$ and combinibg like terms, we get

$168.0\text{T}_{f}\: ^{\circ}\text{C} ^{-1}\:- 2096 = 0]\\$

$T_{f} = \frac{2096}{68.0 \: ^{\circ}\text{C}^{-1}} = 32.4 ^{\circ}\text{C}\\$

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If you were making S’mores [using a chocolate bar, gram-crackers, and marshmallows] at a campfire, would this process be considered a chemical reaction?

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