![Thejedipriest9929](/avatars/42116.jpg)
Thejedipriest9929
13.01.2020 •
Chemistry
In 1987 the first substance to act as a superconductor at a temperature above that of liquid nitrogen (77 k) was discovered. the approximate formula of this substance is yba2cu3o7. calculate the percent composition by mass of this material.
Solved
Show answers
More tips
- F Food and Cooking 10 Tips for Proper Sushi Consumption...
- S Style and Beauty Learn how to tie a keffiyeh on your head like a pro...
- S Style and Beauty How to Braid Hair with a Plaiting Machine: Tips and Recommendations...
- C Computers and Internet Where did torrents.ru move to?...
- H Health and Medicine How to Get Pregnant Faster?...
- A Animals and plants Money Tree Care Secrets: How to Keep Your Plant Thriving...
- S Sport How to Learn to Pull Up on Monkey Bars?...
- H Health and Medicine What was the Invention of Viagra?...
- L Leisure and Entertainment How to Properly Wind Fishing Line onto a Reel?...
- L Leisure and Entertainment How to Make a Crab Trap in Just a Few Minutes...
Answers on questions: Chemistry
- C Chemistry What is the answer to this question?...
- M Mathematics What does the periodic law state? when elements are arranged in order of increasing atomic size, there is a recurring pattern to their physical and chemical properties. when elements...
- S Social Studies How should we deal with collective responsibility for racism?...
- B Business Starting from the situation as depicted by the T-account, if someone deposits $500 into the First Bank of Cantonica, and if the bank makes new loans so as to keep its reserve ratio...
- P Physics Is each genus of organisms is divided into classes?...
Ответ:
The molar mass of the elements are:
Yttrium (Y) = 88.91 g / mol
Barium (Ba) = 137.33 g / mol
Copper (Cu) = 63.55 g / mol
Oxygen (O) = 16 g / mol
Calculating for the molar mass of YBa2Cu3O7:
YBa2Cu3O7 = 88.91 + 2(137.33) + 3(63.55) + 7(16) = 666.22 g / mol
The masses of the elements in 1 mole of YBa2Cu3O7 are:
Yttrium (Y) = 88.91 g / mol (1 mole) = 88.91 g
Barium (Ba) = 137.33 g / mol (2 mole) = 274.66 g
Copper (Cu) = 63.55 g / mol (3 mole) = 190.65 g
Oxygen (O) = 16 g / mol (7 mole) = 112 g
We now calculate for the percent composition by mass of each element:
% Y = 88.91 g / 666.22 g = 13.35%
% Ba = 274.66 g / 666.22 g = 41.23%
%Cu = 190.65 g / 666.22 g = 28.62%
%O = 112 g / 666.22 g = 16.81%
Ответ: