In 2021, you were given a 100. g wine sample to verify its age. Using tritium dating you observe that the sample has 0.688 decay events per minute. Tritium has a half life of 12.3 and fresh water exhibits 5.5 decay events per minute per 100. g. What year was the wine produced
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Ответ:
1984
Explanation:
Given the formula;
0.693/t1/2 = 2.303/t log (Ao/A)
Where;
t1/2 = half life of the radioactive isotope
t= age of the wine
Ao= initial activity of the wine
A= activity of the at time = t
0.693/12.3 = 2.303/t log (5.5/0.688)
0.693/12.3 = 2.079/t
0.056 = 2.079/t
t= 2.079/0.056
t= 37 years
The wine was produced 37 years ago which means that it was produced in the year 1984
Ответ:
0.2 moles of octane
Explanation:
The equation of the reaction is;
C8H18(g) + 25/2 O2(g) > 8CO2(g) + 9H2O(l)
From the equation;
1 mole of octane yields 9 moles of water
x moles of octane yields 1.4 moles of water
x= 1.4 × 1/9
x= 0.16 moles of octane