damienwoodlin6
06.08.2019 •
Chemistry
In the haber process for ammonia synthesis, k " 0.036 for n 2 (g) ! 3 h 2 (g) ∆ 2 nh 3 (g) at 500. k. if a 2.0-l reactor is charged with 1.42 bar of n 2 and 2.87 bar of h 2 , what will the equilibrium partial pressures in the mixture be?
Solved
Show answers
More tips
- H Health and Medicine How to Get Pregnant Faster?...
- S Style and Beauty Lamination of Hair: How it Works and What it is?...
- C Computers and Internet Best Applications for Your iPad: Review of the Best Candidates for Installation...
- S Style and Beauty Intimate Haircut: The Reasons, Popularity, and Risks...
- A Art and Culture When Will Eurovision 2011 Take Place?...
- S Style and Beauty How to Choose the Perfect Hair Straightener?...
- F Family and Home Why Having Pets at Home is Good for Your Health...
- H Health and Medicine How to perform artificial respiration?...
- H Health and Medicine 10 Tips for Avoiding Vitamin Deficiency...
- F Food and Cooking How to Properly Cook Buckwheat?...
Answers on questions: Chemistry
- M Mathematics Number 10 please ???????...
- G Geography What major landform has been created by the interaction of the Eurasian and African plates...
- C Chemistry Use Lewis theory to determine the chemical formula for the compound formed between Al and O....
- E English HEL HURR NO Which uses the best interrogative pronoun to complete the sentence? is going to help me clean and cook all these fish?WhoWhomWhoseWhich...
Ответ:
Answer : The partial pressure of at equilibrium are, 1.133, 2.009, 0.574 bar respectively. The total pressure at equilibrium is, 3.716 bar
Solution : Given,
Initial pressure of = 1.42 bar
Initial pressure of = 2.87 bar
= 0.036
The given equilibrium reaction is,
Initially 1.42 2.87 0
At equilibrium (1.42-x) (2.87-3x) 2x
The expression of will be,
Now put all the values of partial pressure, we get
By solving the term x, we get
From the values of 'x' we conclude that, x = 3.889 can not more than initial partial pressures. So, the value of 'x' which is equal to 3.889 is not consider.
Thus, the partial pressure of at equilibrium = 2x = 2 × 0.287 = 0.574 bar
The partial pressure of at equilibrium = (1.42-x) = (1.42-0.287) = 1.133 bar
The partial pressure of at equilibrium = (2.87-3x) = [2.87-3(0.287)] = 2.009 bar
The total pressure at equilibrium = Partial pressure of + Partial pressure of + Partial pressure of
The total pressure at equilibrium = 1.133 + 2.009 + 0.574 = 3.716 bar
Ответ:
x=B/7-6/7
Step-by-step explanation: