In the reaction of: 2O4 (g) ⇌ 2O2(g) If the equilibrium constant is Kc = 0.513 and the initial concentration of 2O4 = 0.0500 . What are the equilibrium concentrations of 2O4 and O2 under these conditions?
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Ответ:
[N₂O₄] = 0.00411 M
[NO₂] = 0.0918 M
Explanation:
In the reaction of: N₂O₄(g) ⇌ 2 NO₂(g) If the equilibrium constant is Kc = 0.513 and the initial concentration of N₂O₄ = 0.0500 M. What are the equilibrium concentrations of N₂O₄ and NO₂ under these conditions?
Step 1: Given data
Initial concentration of N₂O₄: 0.0500 M
Equilibrium constant (Kc): 0.513
Step 2: Make an ICE chart
N₂O₄(g) ⇌ 2 NO₂(g)
I 0.0500 0
C -x +2x
E 0.0500-x 2x
Step 3: Find the value of "x"
The equilibrium constant is:
Kc = [NO₂]² / [N₂O₄]
0.513 = (2x)² / (0.0500-x)
4x² + 0.513 x -0.02565
We solve for x and we get x₁ = 0.0458942 and x₂ = −0.558894 (neglected).
Step 4: Calculate the concentrations at equilibrium
[N₂O₄] = 0.0500-x = 0.00411 M
[NO₂] = 2x = 0.0918 M
Ответ:
please mark as brainliest
Explanation:
B scientific method