silviarahnama
06.05.2020 •
Chemistry
In your lab you are studying the kinetics of the degradation of a pain killer in the human liver. You are monitoring the concentration of the pain killer over a period of time. The initial concentration of the pain killer in your experiment was 1.84 M. After 2 hours the concentration was found to be 0.92 M. In another 1 hours the concentration was found to be 0.46 M (t = 3 hours overall). If another experiment were set up where the initial concentration of the pain killer was 0.335 M, how long would it take for the pain killer concentration to reach 0.0188 M?
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Ответ:
Hydroxide concentration of the sample is 1.3x10⁻⁶M
Explanation:
The equilibrium constant of water, Kw, is:
H₂O(l) ⇄ H⁺(aq) + OH⁻(aq)
Kw is defined as:
Kw = 1.7x10⁻¹² = [H⁺] [OH⁻]
As the sample is of pure water, both H⁺ and OH⁻ ions have the same concentration because come from the same equilibrium, that is:
[H⁺] = [OH⁻]
We can write the Kw expression:
1.7x10⁻¹² = [OH⁻] [OH⁻]
1.7x10⁻¹² = [OH⁻]²
1.3x10⁻⁶M = [OH⁻]
Hydroxide concentration of the sample is 1.3x10⁻⁶M