In your own words, what was the purpose of this lab? |

answer depends on what lab you are talking about

Explanation:

there are millions of labs out there

Depends what the topic is

Explanation:

The given data is as follows.

      = 0.483,     = 0.173 M,

      = 0.433 M,     = 0.306 M,

      = 9.0 atm

According to the ideal gas equation, PV = nRT

or,             P =    

Also, we know that

                Density =

So,         P = MRT

and,          M =

                    =

                    =

                    = 0.368 mol/L

Now, we will calculate the cell potential as follows.

          E =

             =

             =

             =

             =  0.483 - 0.0185

             = 0.4645 V

Thus, we can conclude that the cell potential of given cell at is 0.4645 V.