Radioactive radon-222 gas (222rn) occurs naturally as a product of uranium decay. the half-life of 222rn is 3.8 days. suppose a flask originally contained 4.0×1013 atoms of 222rn. how many atoms of 222rn will remain after one month (30. days)?
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Ответ:
New mass = original mass × (1/2)n where n is the number of half lives
In this case, the half life is 3 days, thus in 30 days the number of half lives will be 7.895.
Hence, New atoms = 4.0 × 10^13 × (1/2)^7.895
= 1.6805 × 10^11 atoms
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