% ionic character of S8, N2, O3 and bond type

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Ответ:

tiannacorreastamas

30.04.2020

Chemistry

ionic sodium phosphate (Na_3PO_4)

Explanation:

The formula used:

$\Delta T_b=i\times k_b\times m$

$\Delta T_b$ = change in boiling point

i = Van'T Hoff factor

k_b = boiling point constant

m = molality

1. For LiCl

$LiCl\rightarrow Li^{+}+Cl^{-}$

i= 2 as it is ionic and dissociate to give 2 ions.

2. For NaCl

$NaCl\rightarrow Na^{+}+Cl^{-}$

i= 2 as it is ionic and dissociate to give 2 ions.

3. For $C_{12}H_{22}O_{11}$

, i= 1 as it is a non electrolyte and does not dissociate.

4. For $Na_3PO_{4}$

$Na_3PO_4\rightarrow 3Na^{+}+PO_4^{3-}$

, i= 4 as it is ionic and dissociate to give 4 ions.

5. For $MgBr_{2}$

$MgBr_2\rightarrow Mg^{2+}+2Br^-$

, i= 3 as it is ionic and dissociate to give 3 ions.

Thus as vant hoff factor is highest for $Na_3PO_{4}$ , the boiling point will be raised most.

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