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danbelucio
20.10.2020 •
Chemistry
Calculate the pH of a 0.46 M solution of NH 4Cl. ( K b for NH 3 = 1.8 × 10 –5)
a.
9.59
b.
4.41
c.
4.80
d.
0.34
e.
9.20
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Ответ:
pH of the solution = 4.8
Further explanationNH₄Cl is a salt of a weak base and a strong acid so that it will be partially hydrolyzed
Reaction:
NH₄Cl -----> NH₄⁺ + Cl⁻
NH₄ will be hydrolyzed in water
NH₄⁺ + H₂O ------> NH₃ + H₃O⁺ (H⁺)
This solution releases H⁺ ions so they are acidic
Formula
Kw = The water equilibrium constant = 10⁻¹⁴
Kb = the ionization constant of a base = 1.8.10⁻⁵
M = 0.46
[H+]=√2.55 x 10⁻¹⁰ = 1.599 x 10⁻⁵
pH = - log [H+]
pH = 5-log 1.599 = 4.796≈ 4.8
Ответ:
age of light
Explanation: