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paytonrules3634
13.03.2021 •
Chemistry
Is. Fe(s) > Fe2+(aq) + 2e−
oxidation or reduction?
Solved
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Ответ:
Oxidation occurs at the anode: Fe(s) | Fe2+(aq) half cell. (ii) Reduction occurs at the cathode: Ag(s) | Ag+(aq) half cell. Oxidation occurs at the anode: Pt | Sn2+(aq), Sn4+(aq) half cell. (iii) Electrons flow from the anode to the cathode: from the Pt(s) → Ag(s) electrode.
Ответ:
good luch
Explanation:
good luck