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pchisholm100
22.04.2020 •
Chemistry
Jorge conducted an experiment and included the graph shown below as part of his lab report. For his experiment involved which of the following
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Ответ:
Ответ:
Molarity = 0.202 M
7.36 g/L HCl
Explanation:
KOH + HCl > KCl + H2O
1 mol 1 mol
0.560mol/L *0.045L x mol/L*0.125L
0.560mol/L *0.045L = x mol/L*0.125L
x = 0.560mol/L *0.045L /0.125L= 0.2016 mol/L≈ 0.202 mol/L=0.202M HCl
M(HCl) = 1.0+35.5 = 36.5 g/mol
0.2016 mol/L*36.5 g/mol ≈ 7.36 g/L HCl