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23.11.2020 •
Chemistry
Just enough 0.500 M HCl is added to 30.0 mL of 2.5 M NH3 to reach the equivalence point. The Kb of NH3 = 1.8 X 10-5
Write the balanced equation for this reaction.
What volume of 0.500 M HCl solution was added?
What is the molarity of the salt produced from the neutralization reaction?
What is the pH of the solution at the equivalence point?
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Ответ:
a.NH₃+HCl⇒NH₄Cl
b.volume HCl=150 ml
c. pH=4.82
Further explanationReaction
NH₃+HCl⇒NH₄Cl
The equivalence point⇒mol NH₃=HCl
Titration formula :
M₁V₁n₁=M₂V₂n₂(n=acid base valence, NH₃=HCl=1)
mol NH₃
mol HCl=75 mlmol
Volume HCl :Volume total :
molarity of salt(NH₄Cl)mol NH₄Cl=mol NH₃=75 mlmol=0.075 mol
pH of solutionDissociation of NH₄Cl at water to find [H₃O⁺]
ICE at equilibrium :
0.41-x x x
Ka(Kw:Kb)= 10⁻¹⁴ : 1.8.10⁻⁵=5.6.10⁻¹⁰
[H₃O⁺]=x :
pH=-log[H₃O⁺]
Ответ: