KOH + H3AsO4 à K3AsO4 + H2O Given the unbalanced equation above, calculate the moles of potassium arsenate produced from the reaction of 0.125 moles of potassium hydroxide with excess of arsenic acid.
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Ответ:
Answer is in the photo. I couldn't attach it here, but uploaded it to a file hosting. link below! Good Luck!
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Ответ:
17.5 L
Explanation:
Step 1: Given data
Initial volume of the tank of nitrogen (V₁): 14.0 LInitial pressure of nitrogen (P₁): 1 atmFinal volume of the tank of nitrogen (V₂): ?Final pressure of nitrogen (P₂): 0.8 atmStep 2: Calculate the final volume of the nitrogen
We have a gas that undergoes a change at a constant temperature. If we assume an ideal behavior, we can calculate the final volume of the nitrogen using Boyle's law.
P₁ × V₁ = P₂ × V₂
V₂ = P₁ × V₁/P₂
V₂ = 1 atm × 14.0 L/0.8 atm = 17.5 L