Match these items.
1. maximum number of electrons = 2
S
2. maximum number of electrons = 6
р
3. maximum number of electrons = 10
4. maximum number of electrons = 14
f
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Ответ:
-5820,8 kJ
Explanation:
It is possible to sum ΔH of half-reactions to obtain the ΔH of a global reaction (Hess's law).
Using the reactions:
a. 2M(s) + 6HCl(aq) ⟶ 2MCl₃(aq) + 3H₂(g) ΔH₁ = −805.0 kJ
b. HCl(g) ⟶ HCl(aq) ΔH₂= −74.8 kJ
c. H₂(g) + Cl₂(g) ⟶ 2HCl (g) ΔH₃ = − 1845.0 kJ
d. MCl₃(s) ⟶ MCl₃(aq) ΔH₄= −484.0 kJ
The sum of a + 6b + 3c gives:
a. 2M(s) + 6HCl(aq) ⟶ 2MCl₃(aq) + 3H₂(g) ΔH₁ = −805.0 kJ
6b. 6HCl(g) ⟶ 6HCl(aq) ΔH= 6×−74.8 kJ = -448,8 kJ
3c. 3H₂(g) + 3Cl₂(g) ⟶ 6HCl (g) ΔH = 3×−1845.0 kJ = -5535,0 kJ
a + 6b + 3c. 2M(s) + 3Cl₂(g) ⟶ 2MCl₃(aq)
ΔH = -805,0kJ - 448,8 KJ - 5535 kJ = -6788,8 kJ
Now, the sum of this reaction - 2d gives:
a + 6b + 3c. 2M(s) + 3Cl₂(g) ⟶ 2MCl₃(aq) ΔH = -6788,8kJ
-2d 2MCl₃(aq) ⟶ 2MCl₃(s) ΔH= 2×+484.0 kJ
The global reaction gives:
2M(s) + 3Cl₂(g) ⟶ 2MCl₃(s)
ΔH = -6788,8kJ + 2×484.0 kJ = -5820,8 kJ
I hope it helps!