Mention three benefits of obtaining a national senior certificate which is NSC

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mlrood2013oy11gv

29.04.2023

Chemistry

0.42 J

Explanation:

The elastic potential energy of a spring is given by:

$U=\frac{1}{2}kx^2$ (1)

where

k is the spring constant

x is the compression/stretching of the spring

In order to find the elastic potential energy, we must find the spring constant first. We know by Hook's law that the force compressing the spring is:

F=kx

Re-arranging the equation and substituting F=12.0 N and x=0.070 m, we find:

$k=\frac{F}{x}=\frac{12.0 N}{0.070 m}=171.4 N/m$

And now we can use eq.(1) to calculate the elastic potential energy:

$U=\frac{1}{2}(171.4 N/m)(0.070 m)^2=0.42 J$

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Mention three benefits of obtaining a national senior certificate which is NSC​