Mol of an ideal gas expands through a turbine adiabatically to produce work. assuming steady flow conditions, how much work is lost due to the entropy generated, if the surroundings are at 300 k? give the value of lost work to the nearest). inlet conditions: 516.3 k and 6.3 bar outlet conditions: 386.2 k and 1.7 bar cp = (9/2)r where r = 8.314j/mol-k.

Solved

Show answers

Ответ:

heavendl13

17.03.2023

Chemistry

$0.009\times 10^{23}$ molecules.

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 Liters at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

$\text{Number of moles}=\frac{0.0458g}{28.05g/mol}=0.0016moles$ (1g=1000mg)

Now 1 mole of C_2H_4 molecule contains = $6.023\times 10^{23}$ of molecules.

0.0016 moles of C_2H_4 molecule contains = $\frac{6.023\times 10^{23}}{1}\times 0.0016=0.009\times 10^{23}$ molecules.

0,0(0 оценок)

Ask your question to the AI advisor

Ai-bot is an expert in any field and is the perfect companion for reliable and useful answers and advice on a variety of topics, including science, history, technology, art, sports, health, culture and more.

Ask your question

More tips

Answers on questions: Chemistry

Ask an AI advisor a question

I want advice