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sabrinarasull1pe6s61
11.07.2019 •
Chemistry
Na certain city, electricity costs $0.18 per kw·h. what is the annual cost for electricity to power a lamp-post for 6.50 hours per day with (a) a 100.-watt incandescent light bulb (b) an energy efficient 25-watt fluorescent bulb that produces the same amount of light? assume 1 year = 365 days.
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Ответ:
a)
Consumption of power in one day =![100 W \times 6.5 h = 650 Wh](/tpl/images/0078/6057/a7c0d.png)
Consumption of power in one year =![100 W \times 6.5 h\times 365 = 237250 Wh](/tpl/images/0078/6057/f9945.png)
Since,
. So,
Given that
= ![$0.18](/tpl/images/0078/6057/5c2a9.png)
So, for
:
Hence, the annual cost is $
.
b)
Consumption of power in one day =![25 W \times 6.5 h = 162.5 Wh](/tpl/images/0078/6057/fd0ea.png)
Consumption of power in one year =![25 W \times 6.5 h\times 365 = 59312.5 Wh](/tpl/images/0078/6057/754cf.png)
Since,
. So,
Given that
= ![$0.18](/tpl/images/0078/6057/5c2a9.png)
So, for
:
Hence, the annual cost is $
.
Ответ:
Explanation:
H₃O⁺ and H₂O .
H₂O + H⁺ ⇄ H₃O⁺
H₂O accepts proton to form H₃O⁺ so H₂O is base .
H₃O⁺ ⇄ H₂O + H⁺
Here H₃O⁺ is acid because it gives proton ( H⁺ ) .
HCO₃ ⁻ and H₂CO₃
H₂CO₃ ⇄ HCO₃ ⁻ + H⁺
H₂CO₃ is acid because it gives proton ( H⁺ )
HCO₃ ⁻ + H⁺ = H₂CO₃
HCO₃ ⁻ is base because it accepts proton .