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harmonywilliams30
25.01.2021 •
Chemistry
Na2CO3(aq) + CaCl2(aq) — 2 NaCl(aq) + CaCO3(s)
Calculate the volume (in mL) of 0.200 M CaCl, needed to produce 2.00 g of CaCO3(s). There is an excess of Na2CO3.
Molar mass of calcium carbonate = 100.09 g/mol
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Ответ:
100 mL
Explanation:
Given data:
Mass of CaCO₃ produced = 2.00 g
Molarity of CaCl₂ = 0.200 M
Volume of CaCl₂ needed = ?
Solution:
Chemical equation:
Na₂CO₃ + CaCl₂ → 2NaCl + CaCO₃
First of all we will calculate the number of moles of CaCO₃.
Number of moles = mass/molar mass
Number of moles = 2.00 g / 100.09 g/mol
Number of moles = 0.02 mol
Now we will compare the moles of CaCO₃ and CaCl₂.
CaCO₃ : CaCl₂
1 : 1
0.02 : 0.02
Thus, 0.02 moles of CaCl₂ react,
Volume of CaCl₂ reacted:
Molarity = number of moles / volume in L
0.200 M = 0.02 mol / volume in L
Volume in L = 0.02 mol / 0.200 M
Volume in L = 0.1 L
Volume in mL:
0.1 L × 1000 mL/1L
100 mL
Ответ:
The same argument can be made for the process of freezing: energy is put into a liquid during melting, so freezing the liquid into a solid again returns that energy to the surroundings. Like phase changes, chemical reactions can occur with the application or release of heat.