Chemistry: Not yet answered marked out of 2.00 what is the concentration of nh4+ in 60.0 ml of a 0.50 m solution of (nh4)3po4? (to write your answer using scientific notation use 1.0e-1 instead of 1.0 xanswer

8x^4.5, 4x^3Step-by-step explanation:...

Not yet answered marked out of 2.00 what is the - id2002696892, jaylinthornton6

hazeleyes8908

04.01.2022

Answer : The concentration of NH_4^+ ion is 0.15E^1M

Explanation :

First we have to calculate the moles of (NH_4)_3PO_4 .

$\text{Moles of }(NH_4)_3PO_4=\text{Concentration of }(NH_4)_3PO_4\times \text{Volume of solution}=0.50M\times 0.06L=0.03mole$

The balanced chemical reaction will be:

$(NH_4)_3PO_4\rightleftharpoons 3NH_4^++PO_4^{3-}$

From the reaction we conclude that,

1 mole of (NH_4)_3PO_4 dissociate to give 3 moles of NH_4^+ ion and 1 mole of $PO_4^{3-}$ ion

So,

0.03 mole of (NH_4)_3PO_4 dissociate to give $3\times 0.03=0.09$ moles of NH_4^+ ion and 0.03 mole of $PO_4^{3-}$ ion

Now we have to calculate the concentration of NH_4^+ ion.

$\text{Concentration of }NH_4^+=\frac{\text{Moles of }NH_4^+}{\text{Total volume}}$

$\text{Concentration of }NH_4^+=\frac{0.09mole}{0.06L}=1.5M=0.15E^1M$

Therefore, the concentration of NH_4^+ ion is 0.15E^1M

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