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annaebrown9737
29.11.2020 •
Chemistry
Part A
What volume (in mL ) of a 0.150 M HNO3 solution will completely react with 35.7 mL of a 0.108 M Na2CO3 solution according to the following balanced chemical equation?
In the reaction in Part A, what mass (in grams) of carbon dioxide forms?
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Ответ:
Volume HNO₃ : 51.4 ml
Mass CO₂ : 0.17 g
Further explanationReaction
Na₂CO₃ + 2 HNO₃ ⇒ 2 NaNO₃ + CO₂ + H₂O
V Na₂CO₃ = 35.7 ml
M Na₂CO₃ = 0.108
mol Na₂CO₃ :
mol ratio Na₂CO₃ : HNO₃ = 1 : 2
mol HNO₃ :
Volume HNO₃ :
mol CO₂ = mol Na₂CO₃ = 3.8556 mlmol=0.00386 mol
mass CO₂(MW=44 g/mol) :
Ответ:
c
Explanation: