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mazolethrin5672
18.07.2019 •
Chemistry
Phosphine, an extremely poisonous and highly reactive gas, reacts with oxygen gas to form tetraphosphorus decaoxide and water. ph3(g) + o2(g) → p4o10(s) + h2o(g) [unbalanced] calculate the mass of p4o10(s) formed when 225 g of ph3 reacts with excess oxygen.
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Ответ:
The molar mass of PH3 is 34 g/mol, therefore the moles is:
moles PH3 = 225 g / (34 g/mol)
moles PH3 = 6.62 mol
The balanced equation is:
4PH3(g) + 8O2(g) → P4O10(g) + 6H2O
We see that 4 mol of PH3 is required for every mol of P4O10, therefore the number of moles of P4O10 is:
moles P4O10 = 6.62 mol * (1/4)
moles P4O10 = 1.65 mol
The molar mass of P4O10 is 283.89 g/mol, so the mass is:
mass P4O10 = 1.65 mol * 283.89 g/mol
mass P4O10 = 469.67 grams ~ 470 grams
Ответ: