Phosphorus-32 is radioactive and has a half life of 14.3 days. what percentage of a sample would be left after 12.6 days

There is 54.29 % sample left after 12.6 days

Explanation:

Step 1: Data given

Half life time = 14.3 days

Time left = 12.6 days

Suppose the original amount is 100.00 grams

Step 2: Calculate the percentage left

X = 100 / 2^n

⇒ with X = The amount of sample after 12.6 days

⇒ with n = (time passed / half-life time) = (12.6/14.3)

X = 100 / 2^(12.6/14.3)

X = 54.29

There is 54.29 % sample left after 12.6 days

The mineral is broken. If it breaks evenly along a smooth line, it is said to have cleavage. If a mineral doesn't have cleavage, it will break in a ragged line. These minerals are said to have fracture.

Explanation:

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