plants undergo photosynthesis to produce glucose according to the reaction below. what mass of water is required to produce 5.0g of glucose?
6co2 + 6h2o --> c6h12o6 + 6o2

a. 3.0 g h2o
b. 50 g of h2o
c. 5.0 g h2o
d. 18 g h2o

option a) 3 g

Explanation:

mass of Glucose = 5 g

Mass of H₂O = ?

Reaction Given:

                   6CO₂ + 6H₂O > C₆H₁₂O₆ + 6O₂

Solution:

First we have to find mass of glucose from balanced reaction.

So,

Look at the reaction

                        6CO₂ + 6H₂O > C₆H₁₂O₆ + 6O₂

                                     6 mol               1 mol

As 6 mole of water (H₂O) give 1 mole of Glucose (C₆H₁₂O₆ )

Convert moles to mass

molar mass of C₆H₁₂O₆  = 6(12) + 12(1) + 6(16)

molar mass of C₆H₁₂O₆  = 72 + 12 + 96

molar mass of C₆H₁₂O₆= 180 g/mol

molar mass of H₂O = 2(1) + 16 = 18 g/mol

Now

             6CO₂      +  6H₂O          >     C₆H₁₂O₆   +    6O₂

                              6 mol (18 g/mol)           1 mol (180 g/mol)

                                  108 g                            180 g

108 g of water (H₂O) produce 180 g of glucose (C₆H₁₂O₆)

So

if 108 g of water (H₂O) produce 180 g of glucose (C₆H₁₂O₆) so how many grams of water (H₂O) will be required to produce 5 g of glucose (C₆H₁₂O₆).

Apply Unity Formula

               108 g of water (H₂O) ≅ 180 g of glucose (C₆H₁₂O₆)

                X g of water (H₂O) ≅ 5 g of glucose (C₆H₁₂O₆)

Do cross multiply

                     mass of water (H₂O) = 108 g x 5 g / 180 g

                     mass of water (H₂O) = 3 g

So 3 g of water is required to produce 5 g of glucose.