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avablankenship
18.11.2020 •
Chemistry
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Ответ:
I'm not an expert at this, but I assume its mercury.
Ответ:
Silver bromide (AgBr) has a solubility of 7.07 × 10–7 mol/L. A. Write the dissolution. ... A. Write the dissolution reaction of BaF 2 , including all states.
Explanation:Molar solubility is the number of moles that are dissolved in 1 L solution.
when BaF₂ dissolves it dissociates into the following ions
BaF₂ --> Ba²⁺ + 2F⁻
if the molar solubility of BaF₂ is X, then molar solubility of Ba²⁺ is X and F⁻ is 2x
then the formula for the solubility product constant -ksp is;
ksp = [Ba²⁺][F⁻]²
ksp = X * (2X)²
ksp = 4X³
since ksp = 1.7 x 10⁻⁶
4X³ = 1.7 x 10⁻⁶
X = 0.0075 M
molar solubility of BaF₂ is 0.0075m