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diametriagay
11.01.2021 •
Chemistry
Please help me ASAP I’ll mark
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Ответ:
C) √3
tanθ = √3
Step-by-step explanation:
Step:-1
Given that θ be an angle in standard position whose terminal side
Given that the angle
sinθ =![\frac{-\sqrt{3} }{2}](/tpl/images/1229/6336/14690.png)
Given that the Opposite side AB =![\sqrt{3}](/tpl/images/1229/6336/ba4cb.png)
Hypotensue AC = 2
Step(ii):-
By using Pythagoras theorem
AC² = AB² +BC²
BC² = AC² - AB²
BC² = 4 - (√3)²
= 4-3
BC = 1
Adjacent side(BC) = 1
Step(iiI):-
Given that 'θ' lies in the third quadrant so tanθ is positive
tanθ =![\frac{AB}{BC} = \frac{\sqrt{3} }{1}](/tpl/images/1229/6336/4078c.png)