Please help me!
To react with 10 moles of O2, how many moles of AlBr3 are needed?

13.3 mol

Explanation:

Given data:

Number f moles of O₂= 10 mol

Moles of AlBr₃ react = ?

Solution:

Chemical equation:

3O₂ + 4AlBr₃    →      2Al₂O₃ + 12Br

Now we will compare the moles of oxygen and AlBr₃

                      O₂           :            AlBr₃

                       3            :              4

                      10            :             4/3×10 = 13.3 mol

Thus, to react with 10 moles of oxygen  13.3 moles of  AlBr₃ are required.

physical change

Explanation: