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17.08.2020 •
Chemistry
Question 14 (5 points)
What's the acid ionization constant for an acid with a pH of 2.11 and an equilibrium
concentration of 0.30 M?
O A) 4.87x10-8
B) 1.99x10-6
C) 3.32x10-4
OD) 2.01x10-4
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Ответ:
D) 2.01 x 10⁻⁴ .
Explanation:
pH = 2.11
[ H⁺ ] =
Let the acid be HA
It will ionise as follows .
HA ⇄ H⁺ + A⁻
in equilibrium .30
Acid ionisation constant Ka =![\frac{(10^{-2.11})^2}{0.3}](/tpl/images/0723/2348/f0f9c.png)
= 2 x 10⁻⁴
Ответ:
increase the temperature from 27 degrees celsius to 37 degrees celsius
Explanation;The rate of an enzyme-catalyzed reaction increases as the temperature is raised.The human body is maintained at 37°C as this is the temperature at which the enzymes in our body work best. Therefore increasing the temperature from 27 degrees Celsius to 37 degrees Celsius increases enzyme activity and in turn increases the production of amino acid in the flask.Higher temperatures than 37° C which is the optimum temperature, disrupt the shape of the active site, which will reduce enyzme activity, or prevent it from working, in other words the enzyme will have been denatured.