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kinqlouiee2253
04.07.2019 •
Chemistry
Rank the following fertilizers in decreasing order of mass percentage of nitrogen: (nh4)2hpo4 (nh4)2so4 kno3 (nh4)h2po4 nh3 nh4no3
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Ответ:
NH₃ > NH₄NO₃ > (NH₄)₂HPO₄ > (NH₄)₂SO₄ > KNO₃ > (NH₄)H₂PO₄
Soution:In (NH₄)₂HPO₄:
Mass of Nitrogen = N × 2 = 14 × 2 = 28 g.mol⁻¹
Molar Mass of (NH₄)₂HPO₄ = 132.06 g.mol⁻¹
Mass %age = Mass of N / M.Mass of (NH₄)₂HPO₄ × 100
Mass %age = 28 g.mol⁻¹ / 132.06 g.mol⁻¹ × 100
Mass %age = 21.20 %
In (NH₄)₂SO₄:
Mass of Nitrogen = N × 2 = 14 × 2 = 28 g.mol⁻¹
Molar Mass of (NH₄)₂SO₄ = 132.14 g.mol⁻¹
Mass %age = Mass of N / M.Mass of (NH₄)₂SO₄ × 100
Mass %age = 28 g.mol⁻¹ / 132.14 g.mol⁻¹ × 100
Mass %age = 21.18 %
In KNO₃:
Mass of Nitrogen = N × 1 = 14 × 1 = 14 g.mol⁻¹
Molar Mass of KNO₃ = 101.10 g.mol⁻¹
Mass %age = Mass of N / M.Mass of KNO₃ × 100
Mass %age = 14 g.mol⁻¹ / 101.10 g.mol⁻¹ × 100
Mass %age = 13.84 %
In (NH₄)H₂PO₄:
Mass of Nitrogen = N × 1 = 14 × 1 = 14 g.mol⁻¹
Molar Mass of (NH₄)H₂PO₄ = 115.03 g.mol⁻¹
Mass %age = Mass of N / M.Mass of (NH₄)H₂PO₄ × 100
Mass %age = 14 g.mol⁻¹ / 115.03 g.mol⁻¹ × 100
Mass %age = 12.17 %
In NH₃:
Mass of Nitrogen = N × 1 = 14 × 1 = 14 g.mol⁻¹
Molar Mass of NH₃ = 132.14 g.mol⁻¹
Mass %age = Mass of N / M.Mass of NH₃ × 100
Mass %age = 14 g.mol⁻¹ / 17.03 g.mol⁻¹ × 100
Mass %age = 82.20 %
In NH₄NO₃:
Mass of Nitrogen = N × 2 = 14 × 2 = 28 g.mol⁻¹
Molar Mass of NH₄NO₃ = 80.04 g.mol⁻¹
Mass %age = Mass of N / M.Mass of NH₄NO₃ × 100
Mass %age = 28 g.mol⁻¹ / 80.04 g.mol⁻¹ × 100
Mass %age = 34.98 %
Ответ:
lotus
Explanation:
a red colour flower