Relate the chemical structure of carbs to their physical properties and uses

V = 53.82 L

Explanation:

Given data:

Mass of benzene = 45 g

Temperature = 100°C (100+273 = 373 K)

Pressure = 250 torr (250/760 = 0.33 atm)

Volume of benzene = ?

Solution:

Number of moles of benzene:

Number of moles = mass /molar mass

Number of moles = 45 g/ 78.11 g/mol

Number of moles = 0.58 mol

Volume of benzene:

PV = nRT

V = nRT/P

V = 0.58 mol × 0.0821 atm.L/mol.K × 373 k / 0.33 atm

V = 17.76 atm.L /0.33 atm

V = 53.82 L