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esmeraldavelez63
09.10.2019 •
Chemistry
Silver sulfate, ag2so4 (m=311.87), has ksp= 6.0 x10^-5. what mass of ag2so4 will dissolve per liter of water?
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Ответ:
Ag2SO4 = 2Ag^+ + (SO4)^2-
Ksp = [Ag^+]^2 [SO4^2-]
6.0 x10^-5 = 4x^2 (x) = 4x^3
x = 0.025 M
0.025 mol (SO4)^2- / L ( 1 mol Ag2SO4 / 1 mol (SO4)^2-) (311.799 g / mol ) = 7.69 g Ag2SO4 / L solution
Ответ:
produced when the soil was fertiliz