Sodium carbonate (naco3) is sometimes used as a water-softening agent. suppose that a worker prepares a 0.730 m solution of naco3 and water. the volume of the solution is 1.421 liters. what is the mass of solute in the solution?

express your answer to three significant figures.

the mass of dissolved sodium carbonate is

grams

The answer to your question is: 110 g of Na₂CO₃

Explanation:

Data

Na₂CO₃  

concentration = 0.73 M

volume = 1.421 l

MW Na₂CO₃ = (2 x 23) + (12 x 1) + (16 x 3) = 106 g

Process

Molarity = moles / volume

moles = Molarity x volume

moles = 0.73 x 1.421

moles = 1.03733

                                1 mol of Na₂CO₃  106 g

                                 1.03733               x

                                  x = (1.03733 x 106) / 1

                                  x = 109.95 g ≈ 110 g

No because of the equation Hydrogen is brought out of it. This will make the equation uneven therefor it is invalid.

Explanation: