Solve these.. . . . .​

Please find the ten balanced equations below

Explanation:

According to the question, a balanced equation must contain equal number of atoms on both sides of the equation. To balance an equation, coefficients are used. The following are the balanced equation:

1. C + O2 → CO2 (balanced)

2. 2H2 + O2 → 2H2O (balanced)

3. 2Na + 2H2O → 2NaOH + H2 (balanced)

4. 4Na + O2 → 2Na2O (balanced)

5. 2Na + Cl2 → 2NaCl (balanced)

6. NaOH + HCl → NaCl + H2O (balanced)

7. NaOH + HNO3 → NaNO3 + H2O (balanced)

8. 2NaOH + H2SO4 → Na2SO4 + 2H2O (balanced)

9. Na2CO3 + 2HCl → 2NaCl + H2O + CO2 (balanced)

10. 2NaOH + CO2 → Na2CO3 + H2O (balanced)

Step-by-step explanation:

f(4) = 42 + 5 =21, f(-10) = (-10)2 +5 = 105 or alternatively f: x → x2 + 5.

The phrase "y is a function of x" means that the value of y depends upon the value of x, so:

y can be written in terms of x (e.g. y = 3x ).

If f(x) = 3x, and y is a function of x (i.e. y = f(x) ), then the value of y when x is 4 is f(4), which is found by replacing x"s by 4"s .

If f(x) = 3x + 4, find f(5) and f(x + 1).

f(5) = 3(5) + 4 = 19

f(x + 1) = 3(x + 1) + 4 = 3x + 7