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baileytmyers01
baileytmyers01
15.04.2020 • 
Chemistry

Some (CH3)2CHOH is allowed to dissociate into (CH3)2CO and H2 at 452 K. At equilibrium, [(CH3)2CHOH] = 0.218 M, and [(CH3)2CO] = [H2] = 5.11×10-2 M. Additional (CH3)2CO is added so that [(CH3)2CO]new = 9.43×10-2 M and the system is allowed to once again reach equilibrium.
(CH3)2CHOH(g) 7e50f1f7-d29b-4777-b1ee-365a063b4be8.gif(CH3)2CO(g) + H2(g) K = 1.20×10-2 at 452 K

(a) In which direction will the reaction proceed to reach equilibrium? (to the right/to the left)
(b) What are the new concentrations of reactants and products after the system reaches equilibrium?

1.[(CH3)2CHOH] = M
2.[(CH3)2CO] = M
3.[H2] = M

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