Some theories of aging suggest that free radicals cause certain diseases and perhaps aging in general. as you know from lewis theory, such molecules are not chemically stable and will quickly react with other molecules. free radicals may attack molecules within the cell, such as dna, changing them and causing cancer or other diseases. free radicals may also attack molecules on the surfaces of cells, making them appear foreign to the body's immune system. the immune system then attacks the cells and destroys them, weakening the body. draw lewis structures for each of the following free radicals implicated in this theory of aging.
a. o2-
b. o-
c. oh
d. ch3oo(unpaired electron on terminal oxygen)

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Ответ:

potatogirl9300

01.02.2022

Chemistry

Step-by-step explanation:

h(t) = (t + 3)² + 5

A) h(t) = (t + 3)² + 5 -2 ≤ t ≤ 0

average rate of change in h over the change in t is given as:

$\frac{h(0)-h(-2)}{0-(-2)}=\frac{(0+3)^2+5-[(-2+3)^2+5]}{0+2}=\frac{14-6}{2} =4$

It does not have a negative average rate of change

B) A) h(t) = (t + 3)² + 5 -4 ≤ t ≤ -3

average rate of change in h over the change in t is given as:

$\frac{h(-3)-h(-4)}{-3-(-4)}=\frac{(-3+3)^2+5-[(-4+3)^2+5]}{-3+4}=\frac{5-6}{1} =-1$

It have a negative average rate of change

c) A) h(t) = (t + 3)² + 5 -3 ≤ t ≤ 4

average rate of change in h over the change in t is given as:

$\frac{h(4)-h(-3)}{4-(-3)}=\frac{(4+3)^2+5-[(-3+3)^2+5]}{4+3}=\frac{54-5}{7} =7$

It does not have a negative average rate of change

D) h(t) = (t + 3)² + 5 1 ≤ t ≤ 4

average rate of change in h over the change in t is given as:

$\frac{h(4)-h(1)}{4-(1)}=\frac{(4+3)^2+5-[(1+3)^2+5]}{4-1}=\frac{54-21}{3} =11$

It does not have a negative average rate of change

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