Students investigating the reaction between CH3COOH and NaHCO3 obtain .80 g of CO2 from the reaction. Their theoretical yield was 1.0 g. What was their percent yield?

If the actual yield was .80g, and the IDEAL (100%) yield is 1.0g, then put it in the equation & you’ll get 80% yield.

Explanation:

208 g/mol and 87 g/mol

Explanation:

Number of protons = 82

Atomic mass = 126 + 82 = 208 g/mol

For ^{87}Sr

Number of neutrons = 49

Number of protons = 38

Atomic Mass = 49 + 38 = 87 g/mol