Study the scenario and the balanced equation.
While a Bunsen burner is ignited, 7.45 x 1024 mol of methane (CH4) reacts with an excess of oxygen (O2).
CH4(g) + 2O2(g) → CO2(g) + 2H2O(g)
(M H2O = 18.0 g/mol; M CH4 = 16.0 g/mol)
What is the theoretical yield of water produced?
A) 2.68 × 1026 mol H2O
B) 4.14 × 1023 g H2O
C) 4.14 × 1023 mol H2O
D) 2.68 × 1026 g H2O
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Ответ:
Option-D (2.68 × 10²⁶ g of H₂O)
Explanation:
The balance chemical equation for the combustion of Methane is as follow;
CH₄ + 2 O₂ → CO₂ + 2 H₂O
According to balanced equation,
1 mole of CH₄ produced = 2 moles of H₂O
So,
7.45 × 10²⁴ moles of CH₄ will produce = X moles of H₂O
Solving for X,
X = 7.45 × 10²⁴ mol × 2 mol / 1 mol
X = 1.49 × 10²⁵ mol of H₂O
As there is no option containing calculated moles of H₂O produced so, we will convert the moles of H₂O to mass and then look for that answer in given choices.
As,
Mass = Moles × M.Mass
Mass = 1.49 × 10²⁵ mol × 18.01 g/mol
Mass = 2.68 × 10²⁶ g of H₂O
Okay! That's Option-D.
Ответ:
106.2
Explanation:
Multiply the molar mass by three.