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tishfaco5000
27.02.2020 •
Chemistry
Suppose that Daniel has a 3.00 3.00 L bottle that contains a mixture of O 2 O2 , N 2 N2 , and CO 2 CO2 under a total pressure of 4.80 4.80 atm. He knows that the mixture contains 0.230 0.230 mol N 2 N2 and that the partial pressure of CO 2 CO2 is 0.350 0.350 atm. If the temperature is 273 273 K, what is the partial pressure of O 2 O2
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Ответ:
Partial pressure O₂ → 2.74 atm
Explanation:
Let's analyse the data given:
Volume → 3L
In the bottle there is a mixture of gases that contains, O₂, N₂ and CO₂.
Total pressure is 4.80 atm
Let's apply the Ideal Gases Law to determine the total moles of the mixture
P . V = n . R. T
4.80 atm . 3L = n . 0.082 . 273K
n = 4.80 atm . 3L / 0.082 . 273K → 0.643 moles
We apply the concept of mole fraction:
Mole fraction of a gas X = moles of gas X / Total moles
Mole fraction of a gas X = Partial pressure X / Total pressure
In a mixture, sum of mole fraction of each gas = 1
We determine mole fraction of N₂ → 0.230 / 0.643 = 0.357
We determine mole fraction of CO₂ → 0.350 atm / 4.80 atm = 0.0729
1 - mole fraction N₂ - mole fraction CO₂ = mole fraction O₂
1 - 0.357 - 0.0729 = 0.5701 → mole fraction O₂
We replace in the formula: Mole fraction O₂ = Partial pressure O₂ / 4.80 atm
0.5701 . 4.80 atm = Partial pressure O₂ → 2.74 atm
Ответ:
The partial pressure of O2 is 2.73 atm
Explanation:
Step 1: Data given
Volume of the bottle = 3.00 L
Total pressure = 4.80 atm
Moles N2 = 0.230 moles
Partial pressure CO2 = 0.350 atm
Temperature = 273 K
Step 2: Calculate total number of moles
p*V = nRT
⇒ p= the pressure = 4.80 atm
⇒V = the volume = 3.00 L
⇒ n = the number of moles = TO BE DETERMINED
⇒ R = the gas constant = 0.08206 L*atm/K*mol
⇒ T = the temperature = 273 K
n = (pV)/(RT)
n = (4.80*3.00)/(0.08206*273)
n = 0.643 moles
Step 3: Calculate mol fraction CO2
Mol fraction CO2 = partial pressure/ total pressure
Mol fraction CO2 = 0.350 atm / 4.80 atm
Mol fraction CO2 = 0.0729
Step 4: Calculate moles CO2
Moles CO2 = mol fraction * total moles
Moles CO2 = 0.0729 * 0.643 moles
Moles CO2 = 0.0469 moles
Step 5: Calculate moles O2
moles O2 = total moles - moles N2 - moles CO2
moles O2 = 0.643 - 0.230 - 0.0469
moles O2 = 0.3661 moles
Step 6: Calculate mol fraction O2
Mol fraction O2 = 0.3661 / 0.643
mol fraction O2 = 0.569
Step 7: Calculate partial pressure O2
Partial pressure O2 = mol fraction * total pressure
Partial pressure O2 = 0.569 * 4.80 atm
Partial pressure O2 = 2.73 atm
The partial pressure of O2 is 2.73 atm
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