Suppose we want to charge a flask with 1.6 g of sugar. We put the empty flask on a balance and it is determined to weigh 330 g. Enter the weight we would expect to see on the balance when we're done adding the sugar.

total weight to expect = 331.60 grams

Explanation:

The flask wanted to be charged with 1.6 grams of sugar. The empty flask was weighed on a balance and it was determined to weigh 330 grams . The weight we would expect when we add the sugar can be computed as follows:

weight of the empty flask = 330 grams

weight of the sugar = 1.6 grams

The weight of the flask after adding the sugar will be the sum of the weight of the sugar and the empty falsk

Therefore,

Total weight to expect = 330 grams + 1.6 grams

total weight to expect = 331.60 grams

We expect 331.6 grams on the balance

Explanation:

Step 1: Data given

Mass of the empty flask = 330 grams

We want a mass of 1.6 grams of sugar

Step 3: Calculate the total mass

Total mass = mass of empty flask + mass of sugar

Total mass = 330 grams + 1.6 grams sugar

Total mass = 331.6 grams

The total mass of the flask with the sugar should be 331.6 grams

When we have this on the balance we have 1.6 grams of sugar in the flask.

Answer : The boron-11 isotope is the most abundant.

Explanation :

As we are given that:

Average atomic mass of boron = 10.81 amu

Mass of boron-10 = 10.0129 amu

Mass of boron-11 = 11.0093 amu

As we know that the average atomic mass of an element is always closest to the most abundant isotope.

Out of the two boron isotopes, B-11 is closest in mass to the weighted average. Therefore, it is the most abundant.

Hence, the boron-11 isotope is the most abundant.