Table salt, nacl(s), and sugar, c12h22o11(s), are accidentally mixed. a 3.50-g sample is burned, and 2.40 g of co2(g) is produced. what was the mass percentage of the table salt in the mixture?

First we will write the formula for the combustion of the sugar.

C₁₂H₂₂O₁₁ + 12O₂ → 12CO₂ + 11H₂O

We have produced 2.40 g of CO₂. We will convert this to moles of CO₂ and then convert that value to moles of sugar.

2.40 g / 44.0 g/mol = 0.0545 moles CO₂ x 1 mole C₁₂H₂₂O₁₁/12 mole CO₂ = 0.00455 moles of C₁₂H₂₂O₁₁

We can now convert the moles of sugar to a mass of sugar.

0.00455 moles C₁₂H₂₂O₁₁ x 342 g/mol = 1.56 g C₁₂H₂₂O₁₁

We want to determine the mass percentage of salt in the 3.5 g mixture of sugar and salt.

3.5 g mixture - 1.56 g sugar = 1.94 g salt

(1.94 g salt/ 3.5g mixture) x 100% = 55%

Therefore, the mass percentage of table salt in the mixture is 55%.

normal fault

A fault refers to a planar or curved fracture in the rocks of the Earth crust, in which compressional or tensional forces results in the displacement of the rock on the opposite side of the fracture. Fault may vary in the length of the fracture. A normal fault is a fault in which the hanging wall of the rock moves downward to the footwall. It occurs when the two blocks of rock are separated apart by the tensional forces.  

On the basis of the above information, the normal fault is the fault that should be found by the geologists in the rock.