The active ingredient in aspirin is acetylsalicylic acid. a 2.51-g sample of acetylsalicylic acid required 27.36 ml of 0.5106 m naoh for complete reaction. addition of 13.68 ml of 0.5106 m hcl to the flask containing the aspirin and the sodium hydroxide produced a mixture with ph = 3.48. determine the molar mass of acetylsalicylic acid and its ka value. state any assumptions you must make to reach your answer.
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Ответ:
Hey there!
mass of sample = 2.51 g of Aspirin
Number of moles of base ( NaOH ) :
M*V = 27.36*0.5106 = 13.9700 mmol of base
M*V = 13.68*0.516 = 7.05888 mmol of acid
pKa calculation:
pH = pKa + log(A-/HA)
3.48 = pKa + log(7.05888 / (13.9700 -7.05888))
Pka =3.49 - log(7.05888 / (13.9700 -7.05888))
pKa = 3.48
Molar mass calculation:
molar mass = mass/mol
(2.51)/(13.9700 *10⁻³) =
molar mass 180 g/mol approx
Hope that helps!
Ответ:
The new volume of the car tire is approximately 11.784 litres
Explanation:
The initial pressure of the air in the car tire, P₁ = 2.18 atm
The volume occupied by the air in the tire, V₁ = 10.0 L
The new pressure of the air in the tire, P₂ = 1.85 atm.
According to Boyle's Law, we have;
P₁·V₁ = P₂·V₂
Where;
P₁ = The initial pressure of the car tire = 2.18 atm
V₁ - The initial volume of the tire = 10.0 L
P₂ = The new pressure of the tire = 1.85 atm
V₂ = The new volume of the car tire = The required volume
Therefore;
Plugging in the values gives;
The new volume of the car tire, V₂ ≈ 11.784 L.